Sarthaks Test
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Draw the graph of the equation 2x + 3y = 12. From the graph, find the coordinates of the point: 

(i) whose y-coordinates is 3. 

(ii) whose x-coordinate is −3.

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Graph of the equation 2x +3y = 12

We have

2x +3y = 12

2x = 12 -3y

x = (12-3y)/2

Putting y = 2 we get x = (12-3 x 2)/2 = 3

Putting y = -4 we get x = (12-3 x 4)/2 = 0

Thus, (3, 0) and (0, 4) are two points on the line 2x +3y = 12

The graph of line represents by the equation 2x + 3y = 12

(i) To find coordinates of the points when y = 3, we draw a line parallel to x axis and passing through (0,3) this lines meets the graph of 2x + 3y = 12 at a point p from which we draw a line parallel to y axis which process x axis at x =3/2 , so the coordinates of the required points are (3/2, 3).

(ii) To find the coordinates of the points when x = -3 we draw a line parallel to y axis and passing through (-3, 0). This lines meets the graph of 2x +3y = 12 at a point p from which we draw a line parallel to x axis crosses y axis at y = 6, so, the coordinates of the required point are (-3, 6).

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