For any ΔABC, prove that, sin(B+C)/sin(B+C) = (b^2 - c^2)/a^2

Question

For any ΔABC, prove that, \(\frac{sin(B-C)}{sin(B +C)}\) = \(\frac{b^2 - c^2}{a^2}\)

Answer 1

= \(\frac{sin (B-C)}{sin (B +C)} = LHS\)