# In a circle of diameter 40 cm, the length of a cord is 20 cm. Find the length of minor arc of the chord.

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In a circle of diameter 40 cm, the length of a cord is 20 cm. Find the length of minor arc of the chord.

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The radius and chord join to form a equilateral triangle. Therefore

l = rθ = 20 × $\frac{\pi}{3}$

= 20 × $\frac{3.14}{3}$ = 20.933.