Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
761 views
in Linear Inequations by (24.8k points)
closed by

Solve the following systems of inequations graphically : 

12 + 12y ≤ 840, 3x + 6y ≤ 300,8x + 4y ≤ 480, x ≥ 0, y ≥ 0

1 Answer

+1 vote
by (27.0k points)
selected by
 
Best answer

First we will find the solutions of the given equations by hit and trial method and afterwards we will plot the graph of the equations and shade the side with grey color containing common solutions or intersection of the solution set of each inequality, 

You can choose any value but find the two mandatory values which are at x = 0 and y = 0, 

i.e., x and y– intercepts always, 

12 + 12y ≤ 840 

x + y ≤ 70

3x + 6y ≤ 300 

x + 2y ≤ 100

8x + 4y ≤ 480 

2x + y ≤ 120

x ≥ 0, y ≥ 0

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...