Sarthaks Test
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In an isosceles triangle, if the vertex angle is twice the sum of the base angles, calculate the angles of the triangle.

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Let ΔABC be isosceles such that AB = AC.

⇒ ∠B=∠C

Given that vertex angle A is twice the sum of the base angles B and C.

Now,

We know that sum of angles in a triangle = 180°

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