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The path of a train A is given by the equation 3x + 4y − 12 = 0 and the path of another train B is given by the equation 6x + 8y − 48 = 0.

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The path of a train A is given by the equation 3x + 4y − 12 = 0 and the path of another train B is given by the equation 6x + 8y − 48 = 0. Represent this situation graphically.

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We have,

Thus, we have the following table for the points on the line 3x +4y -12 =0:

We have

Thus, we have the following table for the points on the line 6x +8y -48 = 0

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