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In Fig. 10.92, it is given that AB = CD and AD = BC. Prove that ΔADC ≅ ΔCBA.

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Given that in the figure AB =CD and AD=BC

We have to prove  ΔADC ≅ ΔCBA.

Now,

Consider ΔADC and ΔCBA.,

We have

So, by SSS congruence criterion, we have

 ΔADC ≅ ΔCBA.

∴ Hence proved

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