Question

The photograph of a house occupies an area of 1.75 cm²on a 35 mm slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 m². What is the linear magnification of the projector-screen arrangement?

Answer 1

Area of the house on the slide = 1.75 cm² 

Area of the image of the house formed on the screen = 1.55 m² 

= 1.55 × 10⁴ cm²

Arial magnification, m_a = (Area of image/Area of object) = (1.55/1.75) x 10⁴ 

Linear magnifications, ml = √m_a = √(1.55/1.75) x 10⁴ = 94.11