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in Triangles by (32.3k points)
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In ∆ABC, it is given that AB = 9cm, BC = 6cm and CA = 7.5cm. Also, ∆DEF is given such that EF = 8cm and ∆DEF~∆ABC. Then, perimeter of ∆DEF is 

(a) 22.5cm 

(b) 25cm 

(c) 27cm 

(d) 30cm

1 Answer

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Best answer

(d) 30 cm 

Perimeter of ∆ABC = AB + BC + CA = 9 + 6 + 7.5 = 22.5 cm 

∵ ∆DEF ~ ∆ABC

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