0 votes
38.0k views
in Chemistry by (29.8k points)

(a) In ammonia, nitrogen and hydrogen are always present in the ratio 14:3 by mass. State the law which explains the above statement. 

(b) During the formation of ammonia, what mass of hydrogen gas would be required to react completely with 42 g of nitrogen gas? 

1 Answer

+2 votes
by (128k points)
selected by
 
Best answer

(a) In ammonia (NH3) , N and H present in fixed ratio which supports the law of definite or constant proportions. 

This law states, “a pure chemical compound always consists of the same elements that are combined together in a fixed proportion by mass”. 

(b) Molecular mass of ammonia (NH3

= mass of N + mass of H 

= 14 + ( 3 × 1) 

=17 

To react with 14 g N, mass of H required = 3 g 

Therefore to react with 42 g N, mass of H required 

= 3/ 14 ×42 

= 9g.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...