Correct Answer - A::B::C::D
Let `AD=DE =a`
Area of a right isosceles triangle `=49//2sq.cm`
`therefore` Area of square `ADEF,a^2=49`
`rArra=sqrt(49)`
`rArr=a=7cm`
`rArrAD=DE=EF=AF=BC=7cm`
`FB=CE=2DE=14cm`
AB=CD=7+14=21cm`
(a) Perimeter of the square `ADEF=4(7)=28to(q)`
(b) Area of the square `ADEF=49to (r)`
(c) Perimeter of the rectangle `ABCD =2(7+21)=2(28)=56to(p)`
(d) Area of the rectangle `ABCD =(7)(21) =147cm^2to(s)`
Therefore, the correct match is :