Correct Answer - 50 cm
Let l and b be the length and breadth of the rectangle respectively (in cm).
Area of the rectangle `=lb=24sq.cm`
The possible vlaues of `(l,b)=(24,1),(12,2),(8,3), (6,4)`
`therefore` The maximum possible perimeter of the rectangle, `2(l+b)=2(24+1)cm=50cm`.