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In the given figure, two line segment AC and BD intersect each other at the point P such that PA = 6cm, PB = 3cm, PC = 2.5cm, PD = 5cm, ∠APB = 50° and ∠CDP = 30° , then ∠PBA = ?

(a) 50°

(b) 30°

(c) 60°

(b) 100°

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(d)100°

In ∆ APB and ∆ DPC, we have:

 ∠APB = ∠DPC = 50°

AP/BP = 6/3 = 2

DP/CP = 5/2.5 = 2 

Hence, AP/BP = DP/CP 

Applying SAS theorem, we conclude that ∆ APB- ∆ DPC.

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