Given : The word is ‘GANESHPURI.’
To find : number of words in which vowels are always together
Number of vowels in this word = 4(A, E, I, U)
Now,
Consider these four vowels as one entity(AEIU together as a single letter) and arrange these letters
So, the total number of letters = 7(AEIU G N S H P R)
Formula used :
Number of arrangements of n things taken all at a time = P(n, n)
P(n, r) = \(\frac{n!}{(n-r)!}\)
∴ Total number of arrangements
= the number of arrangements of 7 things taken all at a time
= P(7, 7)
= \(\frac{7!}{(7-7)!}\)
= \(\frac{7!}{0!}\)
{∵ 0! = 1}
= 7!
= 7 × 6 × 5 × 4 × 3 × 2 × 1
= 5040
Now,
4 vowels which are together as a letter can be arranged in 4! (like EAIU or AEUI)
= 4 × 3 × 2 × 1
= 24 ways
∴ Total number of arrangements in which vowels come together = 24 × 5040
= 120960