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In a trapezium ABCD, it is given that AB║CD and AB = 2CD. Its diagonals AC and BD intersect at the point O such that ar(∆AOB) = 84cm2 . Find ar(∆COD).

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In ∆AOB and ∆COD, we have:

∠AOB = ∠COD (vertically opposite angle) 

∠OAB = ∠OCD ( alternate angles as AB ǁ CD) 

Applying AA similarity criterion, we get : 

∆ AOB - ∆COD

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