Sarthaks Test
0 votes
2.1k views
in Mathematics by (35.6k points)

ABCD is a rhombus, EABF is a straight line such that EA = AB = BF. Prove that ED and FC when produced meet at right angles.

1 Answer

0 votes
by (61.7k points)
selected by
 
Best answer

We know that the diagonals of a rhombus are perpendicular bisector of each other

In ΔBDE A O , and are mid points of BE and BD respectively

 In ΔCFA B O , and are mid points of AF and AC respectively

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...