Let ABCD be the rhombus with diagonals AC and BD intersecting each other at O.
We know that the diagonals of a rhombus bisect each other at right angles.
∴ If AC – 24 cm and BD = 10 cm, AO = 12 cm and BO = 5 cm
Applying Pythagoras theorem in right-angled triangle AOB, we get:
AB2 = AO2 + BO2 = 122 + 52 = 144 + 25 = 169
AB = 13 cm
Hence, the length of each side of the given rhombus is 13 cm
