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An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach

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An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m.
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rate=-6m/min
Total distance covered=10-(-350)=360m
time=distance covered/Rate
=360/60=60
time 60 min=1 hr.
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