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Ten years ago a father was six times as old as his daughter. After 10 years he will be twice as old as his daughter. Find their present age.

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Ten years ago a father was six times as old as his daughter. After 10 years he will be twice as old as his daughter. Find their present age.
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Let present age of daughter=D
Let present age of father=F
According to question
`F-10=6(D-10)`
`F-10=6D-60`
`F=6D-50-(1)`
`F+10=2(D+10)`
`F+10=2D+20`
`D=15`
F=6*15-50=40.
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