Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
57 views
in Mathematics by (106k points)
closed by
A solid sphere of radius 15 cm is melted & recast into solid right circular cones of radius 20 cm and height 8 cm.Calculate the number of cones created

1 Answer

0 votes
by (98.5k points)
selected by
 
Best answer
Let number of cones created are `x`.
Then, Volume of solid sphere = x*Volume of circular cones
`=>4/3piR^3 = x**1/3pir^2h=> 4R^3 = xr^2h`
Here, `R = 15cm, r = 20cm, h = 8cm`
So, putting these values,
`4**15**15**15 = x**20**20**8`
`=>x = (45**3)/(4**8) = 135/32 = 4.28`
As `x` is the number of circular cones, so it will be a whole number.
`:. x = 4`
So, `4` circular cones will be created.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...