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`PQR` is a triangle right angled at P. If `PQ=10cm and PR=24cm,` find `QR`

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`PQR` is a triangle right angled at P. If `PQ=10cm and PR=24cm,` find `QR`
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According to Question
`QR^2=PQ^2+PR^2`
`QR^2=10^2+24^2`
`QR^2=100+576=676`
QR=26cm.
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