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In Fig. 10.131, prove that:

(i) CD + DA + AB + BC > 2AC

(ii) CD + DA + AB > BC

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Given to prove

(i) CD + DA + AB + BC > 2AC

(ii) CD + DA + AB > BC

From the given figure,

We know that, in a triangle sum of any two sides is greater than the third side

(i) So,

(ii) Now, in , ABC we have

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