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`((27)/(343))^(2/3)xx((343)/(729))^(2/3)div((2401)/(81))^(3/4)`= _____
A. `1//3xx(7//3)^8`
B. `1//9xx(7//3)^7`
C. `1//9xx(7//3)^6`
D. `(7//3)^(6)`

1 Answer

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Best answer
Correct Answer - B
`((27)/(343))^(-2/3)xx((343)/(729))^(2/3)div((2401)/(81))^(3/4)`
`=((3^3)/(7^3))^(-2/3)xx((7^3)/(9^3))^(2/3)div((7^4)/(3^4))^(-3/4)`
`=((3)/(7))^(-2)xx((7^2)/(9^2))div((7)/(3))^(-3)`
`=(7^3)/(3^2xx3^4xx3^3)=(7^7)/(3^9)xx((7)/(9))^7`
Hence the correct option is (b).

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