Given E = {2, 4, 6, 8, 10}

(i) Let A = {x | x = n + 1, n ∈ E}

Thus, for 2 ∈ E, x = 3

4 ∈ E, x = 5,

and so on. Therefore, A = {3, 5, 7, 9, 11}.

(ii) Let B = {x | x = n^{2}, n ∈ E}

So, for 2 ∈ E, x = (2)^{2} = 4, 4 ∈ E, x = (4)^{2} = 16, 6 ∈ E, x = (6)^{2} = 36,

and so on. Hence, B = {4, 16, 36, 64, 100}