Given E = {2, 4, 6, 8, 10}
(i) Let A = {x | x = n + 1, n ∈ E}
Thus, for 2 ∈ E, x = 3
4 ∈ E, x = 5,
and so on. Therefore, A = {3, 5, 7, 9, 11}.
(ii) Let B = {x | x = n2, n ∈ E}
So, for 2 ∈ E, x = (2)2 = 4, 4 ∈ E, x = (4)2 = 16, 6 ∈ E, x = (6)2 = 36,
and so on. Hence, B = {4, 16, 36, 64, 100}