Question

Simple interest on a certain sum is given by `l=(PTR)/(100)`. Make T as the subject of the formula. Find T when P=rs1000, R=10% p.a., and l=rs 300.
A. `T=(100l)/(PR),6` years
B. `T=(100l)/(PR),3` years
C. `T=(100P)/(IR),4` years
D. `T=(100R)/(Pl):5` years.

Answer 1

Correct Answer - B
`I=(PTR)/(100)`
`rArr 100 I=PTRrArr(100I)/(PR)=TrArrT=(100I)/(PR)`
Given `P=rs1000,R=10%` p.a, and `I=300`
`therefore T=(100xx300)/(1000xx10)=3` years.