Sarthaks Test
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ABC is a triangle and through A, B, C lines are drawn parallel to BC, CA and AB respectively intersecting at P, Q and R. Prove that the perimeter of ∆PQR is double the perimeter of ∆ABC.

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Clearly ABCQ and ARBC are parallelograms. 

BC = AQ and BC = AR 

AQ = AR 

A is the midpoint of QR . 

Similarly B and C are the midpoints of PR and PQ respectively.

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