Question

A book with many printing errors contains four different formulas for the displacement y of a particle undergoing a certain periodic motion:

(a = maximum displacement of the particle, v = speed of the particle. T = time-period of motion). Rule out the wrong formulas on dimensional grounds. 

Answer 1

Correct: y = a sin(2πt/T)

Dimension of y = M⁰ L¹ T⁰ 

Dimension of a = M⁰ L¹ T⁰ 

Dimension of L.H.S = Dimension of R.H.S

Hence, the given formula is dimensionally correct.

Incorrect y = a sin vt

Dimension of y = M⁰ L¹ T⁰ 

Dimension of a = M⁰ L¹ T⁰ 

Dimension of vt = M⁰ L¹ T^-1 x M⁰ L⁰ T¹ = M⁰ L¹ T⁰ 

 But the argument of the trigonometric function must be dimensionless, which is not so in the given case. Hence, the given formula is dimensionally incorrect.

Incorrect y = (a/T) sin(t/a)

Dimension of y = M⁰ L¹ T⁰

Dimension of  a/T = M⁰ L¹ T^-1 

Dimension of t/a = M⁰ L^-1 T¹ 

But the argument of the trigonometric function must be dimensionless, which is not so in the given case. Hence, the formula is dimensionally incorrect.

Correct

Since the argument of the trigonometric function must be dimensionless (which is true in the given case), the dimensions of y and a are the same. Hence, the given formula is dimensionally correct.