We know that **Hydrogen H** has **+1** charge and **Oxygen O** has **-2** charge.

Since **H2SO4** molecule is **neutral** so the charges will be balanced by **Sulfur S**

Now balancing the equation gives

2 x (+1) + S + 4 x (-2) = 0

Solving we get,

+2 + S - 8 = 0

S = +6

Thus, **The oxidation number of S in H2SO4 is +6.**