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Tell what property allows you to compute `1 /3 xx (6 xx 4/5) as ( 1/3 xx 6 ) xx 4/3.`

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As per rule of associativity,
`axx(bxxc) = (axxb)xxc`
So,
`1/3xx(6xx4/3) = (1/3xx6)xx4/3`
So, associativity property allows as to compute the given expression.

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