Correct Answer - B
Mass of the empty bottle, `M_(1)`
Mass of the bottle with water, `m_(2)` = 200 g
Mass of the bottle with liquid, `m_(3)` = 400 g
Density of the liquid = 3000 kg, `m^(-3)` = 3 g `cm^(-3)`
density of liquid = `(m_(3)-m_(1))/(m_(2)-m_(1))` `3 = (400-m_(1))/(200-m^(1))`
`400-m_(1)` = 600 - `3m_(1)`
` 2m_(1)` = 200 g,` m_(1)` = 100 g.