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A can do a piece of work in 15 days. B is 50% more efficient than A. B can finish it in 

A. 10 days

B. \(7\frac{1}{2}\) days

C. 12 days

D. \(10\frac{1}{2}\) days

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Number of days required by A to finish the work : 15 days

Work done by A in one day: \(\frac{1}{15}\)

B can work 50% more efficiently than A,

∴ B's one day work = 150% of = \(\frac{150}{100}\times\frac{1}{15}=\frac{1}{10}\)

∴ B alone can complete the work in 10 days.

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