Number of hours A required do a piece of work : 25
Number of hours B required do a piece of work : 20
Work done by A in one hour: \(\frac{1}{25}\)
Work done by B in one hour: \(\frac{1}{20}\)
A works alone for 10 hours, so work completed by A in 10 hours : \(10\times\frac{1}{25}=\frac{2}{5}\)
Work left = \(1-\frac{2}{5}=\frac{3}{5}\)
Work done by A and B together in one hour: \(\frac{1}{25}+\frac{1}{20}=\frac{9}{100}\)
They can do the work together in \(\frac{100}{9}\) hours.
But \(\frac{3}{5}\)th of the work is done by both A and B
∴ Time required to complete \(\frac{3}{5}\)th of the work together by A and B : \(\frac{3}{5}\times\frac{100}{9}=\frac{20}{3}\)hours
∴ Time taken to finish the work: \(\frac{20}{3}=\frac{2}{3}\)hours
