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in Commercial Mathematics by (30.3k points)
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A tap can fill a cistern in 8 hours and another tap can empty the full cistern in 16 hours. If both the taps are open then time taken to fill the cistern is

A. \(5\frac{1}{3}\) hours

B. 10 hours

C. 16 hours

D. 20 hours

1 Answer

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Best answer

Number of hours Tap A requires to fill an empty tank : 8 hours

Number of hours Tap B requires to empty the full tank : 16 hours

Amount of water filled by Tap A in empty tank in one hour: \(\frac{1}{8}\)

Amount of water Tap B empties in one hour: \(\frac{1}{16}\)

Amount of water filled by Tap A and Tap B together in one hour: \(\frac{1}{8}-\frac{1}{16}=\frac{1}{16}\)

∴ They can fill the tank together in 16 hours.

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