A pipe can fill a cistern in: 2 hours
Let a leak empty the cistern in: X hours
Due to the leak time taken to fill the cistern : \(2\frac{1}{3}=\frac{7}{3}\) hours
Part of the cistern filled by pipe in one hour: \(\frac{1}{2}\)
Part of the cistern emptied by leak in one hour: \(\frac{1}{x}\)
X = 14 hours
Therefore the leak will empty the cistern in 14 hours.
