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A works twice as fast as B. If both of them can together finish a piece of work in 12 hours, then B alone can do it in 

A. 24 hours 

B. 27 hours 

C. 36 hours 

D. 18 hours

1 Answer

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Best answer

Work done by A in one hour: 2x 

Work done by B in one hour: x 

Number of days taken by A and B to do the work together: 12 hours

Work done by A and B together in one hour: \(\frac{1}{12}\)

\(\frac{1}{12}\) = 2x + x

\(\frac{1}{12}\) = 3x

X = \(\frac{1}{36}\)

Here X is Work done by B in one hour

∴ B alone will take 36 hours to complete the work.

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