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Is it possible to have a regular polygon each of whose exterior angles is 50°?

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No, since \(\frac{360}{50}\) is not a whole number

Sum of exterior angles of regular polygon is 360° 

When we divide the exterior angle by 360°, we get the numbers of exterior angle. 

Since, it is a regular polygon number of exterior angles will be equal to number to sides. 

N = 360/50 = 7.2 [Number of sides of polygon] 

7.2 is not an integer. So, it is not possible to have a regular polygon whose each exterior angle is 50°.

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