We are given width of each section is same.
`:.` Width of each section will be `= 8/2 = 4cm`
Now, `ar(E EGH) = 24**20 = 480cm^2`
`ar(AEHD)=ar(BFGC) = 1/2(`Sum of parallel sides`)(`width`)` `= 1/2(32+24)**4 = 112cm^2`
`ar(CGHD) = ar(AEFB) = 1/2(20+28)**4 = 96cm^2`
`ar(ABCD) = 32**28 = 896cm^2`