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The adjacent figure shows the diagram of a picture frame having outer dimensions 28 cm x 32 cm and inner dimensions 20 cm x 24 cm If the width of each section is the same find the area of each section of the frame

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We are given width of each section is same.
`:.` Width of each section will be `= 8/2 = 4cm`
Now, `ar(E EGH) = 24**20 = 480cm^2`
`ar(AEHD)=ar(BFGC) = 1/2(`Sum of parallel sides`)(`width`)` `= 1/2(32+24)**4 = 112cm^2`
`ar(CGHD) = ar(AEFB) = 1/2(20+28)**4 = 96cm^2`
`ar(ABCD) = 32**28 = 896cm^2`

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