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In a circle of radius 13 cm, AB and CD are two equal and chords of lengths 24 cm each .What is the distance between the chords ?

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In the given circle with centre O,AB and CD are the two chords each of length 24 cm and are equidistant from the centre of the circle. Therefore the distance between AB and `CD=2sqrt(OB^(2)-EB^(2))=2sqrt(13^(2)-((24)/(2))^(2))=10cm`
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