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Divide `z (5z^2-80)` by `5z(z+4)`

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Divide `z (5z^2-80)` by `5z(z+4)`
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`z(5z^2 - 8) = 5z(z^2 - 16)`
`= 5z(z-4)(z+4)`
`=> 5z(z+4) = 5*z*(z+4)`
`(z(5z^2 - 80))/(5z(z+4)) = (5*z*(z-4)(z+4))/(5*z*z*4)`
`= z-4`
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