Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
129 views
in Mathematics by (98.5k points)
closed by
Carry out the following divisions. (i) `28x^4 -: 56x` (ii) `-36y^3 -: 9y^2` (iii) `66pq^2r^3 -: 11qr^2` (iv) `34x^3y^3z^3 -: 51xy^2z^3` (v) `12a^8b^8 -: (-6a^6b^4)`

1 Answer

0 votes
by (106k points)
selected by
 
Best answer
(i) `(28x^4)/(56x) = (28**x**x3)/(2**28**x) = x^3/2`
(ii)`(-36y^3)/(9y^2) = (-4**9**y^2**y)/(9**y^2) = -4y`
(iii)`(66pq^2r^3)/(11qr^2) = (6**11**p**q**q**r**r^2)/(11**q**r^2) = 6pqr`
(iv)`(34x^3y^3z^3)/(51xy^2z^3) = (2**17**x**x^2**y**y^2**z^3)/(3**17**x**y^2**z^3)=(2x^2y)/3`
(v)`(12a^8b^8)/(-6a^6b^4) = (2**6**a^6**a^2**b^4**b^4)/(-6**a^6**b^4) =-2a^2b^4`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...