Question

What is the probability that a leap year has 53 Sundays and 53 Mondays?

Answer 1

Given: a leap year which includes 52 weeks and two days

Formula: P(E) = \(\frac{favourable \ outcomes}{total \ possible \ outcomes}\) 

so, we have to determine the probability of that remaining two days are Sunday and Monday 

S= {MT, TW, WT, TF, FS, SSu, SuM}

Therefore n(S)=7 

E= {SuM} 

n(E)=1 

P(E) = \(\frac{n(E)}{n(S)}\) 

P(E) = \(\frac{1}{7}\)