Let \(\angle\)A, \(\angle\)B, \(\angle\)C and \(\angle\)D are the four angles of quadrilateral.
As we know that, Sum of all four angles of quadrilateral is 360o.
\(\angle\)A = 76°
\(\angle\)B = 54°
\(\angle\)C = 108°
So, \(\angle\)D = 360o - (\(\angle\)A + \(\angle\)B + \(\angle\)C)
= 360o – (76° + 54° + 108°)
= 122o
So, fourth angle of quadrilateral will be 122o .