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Two angles of a quadrilateral measure 85° and 75° respectively. The other two angles are equal. Find the measure of each of these equal angles.

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Let x be the common angle of quadrilateral. 

As per question,

\(\angle\)A = 85°

\(\angle\)B = 75°

\(\angle\)C = \(\angle\)D = x

As we know that, Sum of all four angles of quadrilateral is 360o

\(\angle\)A + \(\angle\)B + \(\angle\)C + \(\angle\)D = 360°

85° + 75°+ x + x = 360°

2x = 360° - (85° + 75°)

2x = 200°

X = 200 / 2

= 100°

\(\angle\)C = \(\angle\)D = 100°

So, Two angles of quadrilateral whose measuring’s are equal is 100°.

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