Question

A piece of work can be done by 16 men in 8 days working 12 hours a day. How many men are needed to complete another work, which is three times the first one, in 24 days working 8 hours a days ?

Answer 1

Using the formula,`(M_(1)D_(1)H_(1))/(W_(1))=(M_(2)D_(2)H_(2))/(W_(2))`
Let `W_(1)=x` and `W_(2)=3x`
`M_(1)`=16,`H_(1)`=12,`D_(1)`=8
`H_(2)`=8,`D_(2)`=24
`:. (16xx8xx12)/(x)=(M_(2)xx24xx8)/(3x)`
`implies M_(2)=24` men.