Sarthaks Test
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in Mathematics by (35.6k points)

In the below fig. ABCD is a trapezium in which AB || DC and DC = 40 cm and AB = 60 cm. If X and Y are respectively, the mid-points of AD and BC, prove that: 

(i) XY = 50 cm 

(ii) DCYX is a trapezium 

(iii) ar (trap. DCYX) = 9/11 ar (trap. (XYBA))

1 Answer

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(i) Join DY and produce it to meet AB produced at P

(ii) We have

XY || AP

(iii) Since x and y are the midpoint of DA and CB respectively 

Trapezium DCXY and ABYX are of the same height say hm 


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