Let ABCD be a rhombus with diagonals AC and BD.
AC and BD bisect at O.
So, AO = \(\frac{16}{2}\) = 8 cm
And BO = \(\frac{12}{2}\) = 6 cm
In right angled triangle AOB,
AB2 = AO2 + OB2 (According to Pythagoras theorem)
AB2 = 82 + 62
AB2 = 64 + 36
AB = \(\sqrt{100}\)
= 10 cm.
So, Length of Rhombus of each side is 10 cm.