Question

An effort applied on the small piston of a hydraulic jack lifts the load through a distance of 50 cm and the effort is displaced through 2 m. If the diameter of the larger piston is 28 cm, calcualte the area of the cross section of the smaller piston.

Answer 1

`d_(1)=50 cm`
`therefore M.A. (L)/(E )=(d_(E ))/(d_(L))=(2)/(0.5)=4`
`4=(pi_(2)^(2))/(pi r_(1)^(2))`
`4=((22)/(7)xx0.14xx0.14)/(A_(1))`
`A_(1)=0.0154`