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+1 vote
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in Combinations by (25.0k points)
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Let r and n be positive integers such that 1 ≤ r ≤ n. Then prove the following : 

n.n – 1Cr – 1 = (n – r + 1)(nCr – 1)

1 Answer

+1 vote
by (27.2k points)
selected by
 
Best answer

Given that we need to prove : 

n.n – 1Cr – 1 = (n – r + 1).nCr – 1 

Consider L.H.S, 

We know that,

nCr\(\frac{n!}{r!(n-r)!}\)

And also,

n! = n(n – 1)(n – 2)…………2.1

= R.H.S 

∴ L.H.S = R.H.S, 

Thus proved.

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