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In Fig. 10.32, AB is a diameter of the circle, CD is a chord equal to theradius of the circle. AC and BD when extended intersect at a point E. Prove t

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In Fig. 10.32, AB is a diameter of the circle, CD is a chord equal to theradius of the circle. AC and BD when extended intersect at a point E. Prove that`/_A E B = 60^@`
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OC=OD=CD
equilateral triangle
`/_COD=60^0`
`/_COD=2/_CBD`
`/_CBD=30^0`
`/_ECB=90^0`
In `/_ECB`
`/_ECB+/_CBE+/_CEB=180^0`
`/_CEB=180^0`
`/_CEB=180-90-30=60^0`.
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